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72b^2-48b=0
a = 72; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·72·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*72}=\frac{0}{144} =0 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*72}=\frac{96}{144} =2/3 $
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